Complete Question:
From a point along a straight road, the angle of elevation to the top of a hill is 33° . A distance of 200 ft farther down the road, the angle of elevation to the top of the hill is 20°. How high is the hill?
Answer:
The hill is 165.87 ft high
Step-by-step explanation:
Check the file attached below for a pictorial understanding of the question
[tex]tan \theta = \frac{opposite}{Adjacent}[/tex]
From ΔABC
[tex]tan 33 = \frac{y}{x} \\[/tex]
[tex]y = x tan 33[/tex]..........(1)
From ΔABD
[tex]tan 20 = \frac{y}{x + 200} \\[/tex]
[tex]y = (x + 200) tan 20[/tex]............(2)
Equating (1) and (2)
[tex]x tan 33 = (x+200) tan20\\xtan33 = xtan20 + 200tan20\\0.649x = 0.364x + 72.794\\0.649x - 0.364x = 72.794\\0.285x = 72.794\\x = 72.794/0.285\\x = 255.42 ft[/tex]
Substitute the value of x into equation (1)
[tex]y = 255.42 tan 33[/tex]
y = 165.87 ft