Answer:
22\pi m
Step-by-step explanation:
Given:
Diameter is 9 m and the outer part of the circle is 2 m
To find: difference between the circumference of the outer circle and the circumference of the inner circle
Solution:
Diameter of inner circle = 9 m
Radius of the inner circle (r) [tex]=\frac{9}{2}=4.5\,\,m[/tex]
Circumference of the inner circle [tex]=\pi r^2=\pi (4.5)^2[/tex]
As outer part of the circle is 2 m,
outer radius (R) = r + 2 = 4.5 + 2 = 6.5 m
Circumference of the outer circle [tex]=\pi R^2=\pi (6.5)^2[/tex]
So,
difference between the circumference of the outer circle and the circumference of the inner circle [tex]=\pi (6.5)^2-\pi (4.5)^2=\pi\left [ (6.5)^2-(4.5)^2 \right ]=\pi\left ( 42.25-20.25 \right )=22\pi[/tex] m