Question

A solution with a ph of 2 has how many more protons in it than a solution with a ph of 4?

Answer 1

Given question is incomplete. The complete question is as follows.

A solution with a ph of 2 has how many more protons in it than a solution with a ph of 4?

(a) 100 times more.

(b) 5 times more.

(c) 1000 times more.

(d) 10 times more.

Explanation:

Concentration of hydrogen ion for a solution with pH = 2 will be calculated as follows.

              pH = $-log [H^{+}]$

               2 = $-log [H^{+}]$

              $antilog 2 = [H^{+}]$

                $[H^{+}] = 10^{-2}$

Concentration of hydrogen ions= for a solution with pH = 4 will be calculated as follows.

             pH = $-log [H^{+}]$

              4 = $-log [H^{+}]$

           $antilog 4 = [H^{+}]$

           $10^{-4} M = [H^{+}]$

Now, let us assume that volume of both the solutions is V ml.

Hence, mole of $H^{+}$ in pH = 2 will be calculated as follows.

          $10^{-2} mol/L \times V$

                 = $10^{-2} V mol$

Mole of $H^{+}$ in pH = 4 will be calculated as follows.

          $10^{-4} mol/L \times V$

                 = $10^{-4} V mol$

So,     $\frac{\text{mole of H^{+} (pH = 2)}}{\text{mole of H^{+} (pH = 4)}}$

                            = $\frac{10^{-2} V mol}{10^{-4} V mol}$

                            = 100

Hence, mole of $H^{+}$ pH equal to 2 = 100 mole of

Thus, we can conclude that a solution with pH of 2 has 100 times more protons in it than a solution with a pH of 4.