A manufacturing company has been selected to assemble a small but important component that will be used during the construction of numerous infrastructure projects. The company anticipates the need to assemble several million components over the next several years. Company engineers select three potential assembly methods: Method A, Method B, and Method C. Management would like to select the method that produces the fewest number parts per 10,000 parts produced that do not meet specifications. It may also be possible that there is no statistical difference between the three methods in which case the lowest cost method will be selected for production. While all parts are checked before leaving the factory, the best method will reduce the number of parts that need to be recycled back into the production process.To test each method, six batches of 10,000 components are produced using each of the three methods. The number of components out of specification are recorded in the Microsoft Excel Online file below. Analyze the data to determine if there is any difference in the mean number of components that are out of specification among the three methods. After conducting the analysis report the findings to the management team.a. Compute the sum of squares between treatments (assembly methods).b. Compute the mean square between treatments (to 1 decimal if necessary).c. Compute the sum of squares due to error.d. Compute the mean square due to error (to 1 decimal if necessary).

Al the = .05 level of significance test whether the means for the three treatments are equal. Calculate the value of the VA statistic ( o 2 decimals).

Test Statistics F = 5.50

The p-value M 0.0162

What is your conclusion? Reject the null hypothesis. There is a significant difference between the treatments effects. The p-value is between 0.01 and 0.025. Conclude that the means for all the treatments are not equal.