Question

Parallelogram MNPQ has vertices at M(5,14), N(10,16), P(12,11), Q(7,9). Just using the Diagonals,
which figure(s) could this possibly be before checking the side lengths? SELECT ALL THAT APPLY.

Answer 1

Answer:

square

Step-by-step explanation:

You use the Pitagora's theorem to calculate the diagonals of the figure.

The diagonals are given by the distance NQ and MP.

By calculating the value of these diagonals you have:

$d_{NQ}=\sqrt{(10-7)^2+(16-9)^2}=\sqrt{58}\\\\d_{MP}=\sqrt{(12-5)^2+(11-14)^2}=\sqrt{58}$

These diagonlas are equal between them. Hence, the figure is a square