Question

tandard reduction potentials are 1.455 V for the PbO2(s)/Pb(s) couple, 1.82 V for Co3 (aq)/Co2 (aq), 3.06 V for F2(g)/HF(aq), 1.07 V for Br2(l)/Br-(aq), and 1.77 V for H2O2(aq)/H2O(l). Under standard-state conditions, arrange the oxidizing agents in order of decreasing strength.

Answer 1

Answer:

F2(g)/HF(aq)>Co3 (aq)/Co2 (aq)> H2O2(aq)/H2O(l)> PbO2(s)/Pb(s)>Br2(l)/Br-(aq)

Explanation:

The tendency to function as oxidizing agent depends on the reduction potential of the couple. The more positive the reduction potential of the couple, the better it does as an oxidizing agent.

This means that one could know a good oxidizing agent by simply looking at reduction potentials. The couple with the greatest (most positive) reduction potential is the best oxidizing agent. If there are a number of couples at different reduction potentials, the order of oxidizing ability can be deduced by arranging the species in order of decreasing positive reduction potentials. Hence the answer.