Answer:
An adult male Komodo dragon is [tex]10\frac12[/tex] feet.
Therefore the male is [tex]1\frac34[/tex] feet longer than the mother.
Step-by-step explanation:
Given that,
A baby dragon is [tex]1\frac34[/tex] feet long.
It's mother is [tex]8\frac34[/tex] feet.
An adult male Komodo dragon is 6 times as long as the baby Komodo dragon.
So, an adult male Komodo dragon is =(6×[tex]1\frac34[/tex] ) feet
[tex]=6\times \frac74[/tex] feet
[tex]=\frac61\times \frac74[/tex] feet
= [tex]\frac {21}2[/tex] feet.
[tex]=10\frac12[/tex] feet.
[tex]\therefore 10\frac 12- 8\frac34[/tex]
[tex]=\frac{21}{2}-\frac{35}4[/tex]
[tex]=\frac{21\times 2-35\times 1}{4}[/tex]
[tex]=\frac{42-35}{4}[/tex]
[tex]=\frac74[/tex]
[tex]=1\frac34[/tex]
Therefore the male is [tex]1\frac34[/tex] feet longer than the mother.
