Question

The constraint 5x 1 + 3x 2 ≤ 150 is modified to become a goal equation, and priority one is to avoid overutilization. Which of the following is appropriate? a. Min P1d1− ; 5x1 + 3x2 + d1− − d1+ = 150 b. Min P1d1+ ; 5x1 + 3x2 + d1− − d1+ = 150 c. Min P1d1+ ; 5x1 + 3x2 + d1+ = 150 d. Min P1d1+ ; 5x1 + 3x2 − d1+ = 150

Answer 1

Answer:

c. Minimize P,d1+; 5x1 + 3x2 + d1+ = 150

Step-by-step explanation:

5x1 + 3x2 = 150. To convert an equality, we simply add an “artificial” variable (d1) to the equation: 5X1 + 3X2 + d1 = 150 An artificial variable is a variable that has no physical meaning in terms of a real-world LP problem. It simply allows us to create a basic feasible solution to start the simplex algorithm. An artificial variable is not allowed to appear in the final solution to the problem. Here in this problem to avoid over utilization, we introduce this artifical variable.

Answer 2

This question is based on concept on linear programming problem. Therefore, the appropriate option is C,  Min $P_1d_1$+ ; $5x_1 + 3x_2 + d_1\leq 150$.

Given:

The constraint $5x_1 + 3x_2\leq 150$ is modified to become a goal equation, and priority one is to avoid overutilization.

We have to choose most appropriate option for above question.

According to the question,

Now, converting an given equality, we simply add an “artificial” variable (d1) to the equation:

We get,

$5x_1 + 3x_2 + d_1\leq 150$

An artificial variable is a variable that has no physical meaning in terms of a real-world linear programming problem.

It simply allows us to create a basic feasible solution to start the simplex algorithm.

This variable is not allowed to appear in the final solution to the problem. Here, to avoid over utilization, we introduce this artificial variable.

Therefore, the appropriate option is C,  Min $P_1d_1$+ ; $5x_1 + 3x_2 + d_1\leq 150$.

For more details, prefer this link:

https://brainly.com/question/19504567