Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation =v9.8d. If a wave formed in shallow water has a velocity of 5.2 meters per second, what is the water's depth? Carry your intermediate computations to at least four decimal places, and round your answer to the nearest tenth.

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The clear question is;

Suppose that a wave forms in shallow water. Then the depth d of the water (in meters) and the velocity v of the wave (in meters per second) are related by the equation v=√9.8d . If the wave formed in shallow water has a velocity of 5.2 meters per second, what is the water’s depth? Carry your intermediate computation to at least four decimal places, and round your answer to the nearest tenth

Answer:

Water's depth;d ≈ 2.8 m

Explanation:

We are told that the relationship between the velocity and depth of the water is given by;

v = √9.8d

Where;

v is the velocity of the wave and d is the depth of the water

Now, we are given velocity; v = 5.2 m/s.

Thus, plugging it into the relation above, we have;

5.2 = √9.8d

Let's take the square of both sudes to get;

5.2² = 9.8d

27.04 = 9.8d

Let's divide both sides by 9.8 to get;

9.8d/9.8 = 27.04/9.8

d = 2.7592m

We are told to approximate to nearest tenth.

Thus, d ≈ 2.8 m

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