Answer:
[tex]Tan \theta= \dfrac{4}{3}[/tex]
Step-by-step explanation:
Given:
The terminal side of an angle in standard position passes through P(-3,-4).
- Point P is in Quadrant III
- In Quadrant |||, [tex]Tan \theta[/tex] is positive.
[tex]Tan \theta= \dfrac{Opposite}{Adjacent}\\Tan \theta= \dfrac{y}{x}\\Tan \theta= \dfrac{-4}{-3}\\Tan \theta= \dfrac{4}{3}[/tex]
