According to a study of political​ prisoners, the mean duration of imprisonment for 30 prisoners with chronic​ post-traumatic stress disorder​ (PTSD) was 30.6 months. Assuming that sigmaequals42 ​months, determine a 95​% confidence interval for the mean duration of​ imprisonment, mu​, of all political prisoners with chronic PTSD. Interpret your answer in words.

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Answer:

The 95​% confidence interval for the mean duration of​ imprisonment, mu​, of all political prisoners with chronic PTSD is between 15.57 months and 45.63 months.

This means that we are 95% sure that the true mean mean duration of​ imprisonment, mu​, of all political prisoners with chronic PTSD is between 15.57 months and 45.63 months.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{42}{\sqrt{30}} = 15.03[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 30.6 - 15.03 = 15.57 months

The upper end of the interval is the sample mean added to M. So it is 30.6 + 15.03 = 45.63 months

The 95​% confidence interval for the mean duration of​ imprisonment, mu​, of all political prisoners with chronic PTSD is between 15.57 months and 45.63 months.

This means that we are 95% sure that the true mean mean duration of​ imprisonment, mu​, of all political prisoners with chronic PTSD is between 15.57 months and 45.63 months.

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