Answer:
Two solutions x=-5.12 and x=3.12
Step-by-step explanation:
x^2+2x+1=17
Subtract 17
so x^2+2x-16
Then solve using the quadratic formula
so x=[tex]\frac{-2+or-\sqrt{2^2-4*1*(-16)}}{2*1}[/tex]
solve x=[tex]\frac{-2+or-\sqrt{4+64} }{2}[/tex]
Separate the equations into two x= equations of + or -
x=[tex]\frac{-2+2\sqrt{17} }{2}[/tex]
and x= [tex]\frac{-2-2\sqrt{17} }{2}[/tex]
x=-5.12
x=3.12