Surgery is in 4 out if every 10 hospital emergency room visits. If a large urban hospital had 840 emergency visits in the past month how many of these visits would you expect to required surgery

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Answer:

Expected number of visits to the emergency room that would require a surgery is 336.

Step-by-step explanation:

Let X = number of surgery.

The odds of having a surgery in a randomly selected visit to a emergency room is 4 out of 10.

Then the probability of having a surgery in a randomly selected visit to a emergency room is:

[tex]p=\frac{4}{10}=0.40[/tex]

In the past month a large urban hospital had 840 emergency visits.

An emergency room visit may lead to surgery or not is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 840 and p = 0.40.

The expected value of a binomial random variable is:

[tex]E(X)=np[/tex]

Compute the expected number of visits that would require a surgery as follows:

[tex]E(X)=np[/tex]

         [tex]=840\times 0.40\\=336[/tex]

Thus, expected number of visits to the emergency room that would require a surgery is 336.

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