Answer:
62.50 units
$3,866.25
Explanation:
The price function is:
[tex]p = 130 - Q[/tex]
[tex]C = 40+5Q[/tex]
Profit as a function of quantity (P(Q)) is given by:
[tex]P(Q) = Q*p(Q) - C(Q)\\P(Q) = Q*(130-Q)-40-5Q\\P(Q) = -Q^2+125Q-40[/tex]
The quantity for which the derivate of the profit function is zero is the profit maximizing quantity:
[tex]P(Q) = -Q^2+125Q-40\\P'(Q) =0= -2Q+125\\Q=62.50\ units[/tex]
The profit-maximizing quantity is 62.50 units
The economic profit for this production volume is:
[tex]P(62.5) = -(62.5^2)+125*62.5-40\\P(62.5)=\$3,866.25[/tex]
The firm earns a profit of $3,866.25.