Answer:
[tex]A=10,000(1+\frac{0.04}{4})^{4(5)}[/tex]
Step-by-step explanation:
For a problem like this, we would use the compound interest formula:
[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]
P = initial balance
r = interest rate (decimal)
n = number of times compounded annually
t = time
First, lets change 4% into a decimal:
4% -> [tex]\frac{4}{100}[/tex] -> 0.04
Since the interest is compounded 4 times a year, we will use 4 for n.
The equation is shown below:
[tex]A=10,000(1+\frac{0.04}{4})^{4(5)}[/tex]
Answer:
C) A = 10,000(1.01)^20
Step-by-step explanation:
just took the same question