Answer:
Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \geq[/tex] 60 tissues
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 60 tissues
Step-by-step explanation:
We are given that 60 tissues is the mean number of tissues used during a cold.
Suppose a random sample of 100 Kleenex users yielded the following data on the number of tissues used during a cold: sample mean = 52, sample std deviation = 22.
Let [tex]\mu[/tex] = mean number of tissues used during a cold.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \geq[/tex] 60 tissues
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 60 tissues
Here, null hypothesis states that the mean number of tissues used during a cold is more than or equal to 60.
On the other hand, alternate hypothesis states that the mean number of tissues used during a cold is less than 60.
The test statistics that would be used here is One-sample t test statistics as we don't know about population standard deviation i.e;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
Hence, the above hypothesis is appropriate for the given situation.