Question

On a trip, you notice that a 2.27 kgbag of ice lasts an average of 1 day in your cooler. What is the average power absorbed by the ice if the ice starts at 0∘C and completely melts to liquid water at 0∘C in exactly 1 day? The latent heat of fusion for water is 334 kJ/kg.

Answer 1

Answer:8.77 W

Explanation:

Given

mass of ice $m=2.27\ kg$

Latent heat of fusion $L=334\ KJ/kg$

1 day is equivalent to 24 hr

$24\approx 8.64\times 10^4\ s$

Heat required to melt ice completely

$Q=mL$

$Q=2.27\times 334=758.18\ kJ$

Average power absorbed by ice $P$

$P_{avg}=\frac{Q}{\Delta t}$

$P_{avg}=\frac{758.18}{8.64\times 10^4}$

$P_{avg}=8.77\ W$