Answer:
The probability of rolling a number less than or equal to 2, then rolling a prime number is [tex]\frac{1}{6}[/tex].
Step-by-step explanation:
The sample space of rolling a number cube, numbered 1 - 6 is:
S = {1, 2, 3, 4, 5, 6}
The cube is rolled twice.
Denote the events as follows:
A = rolling a number less than or equal to 2 in the first roll
B = rolling a prime number in the second roll
The two events A and B are independent.
This is because the result of rolling the cube the second time will not be dependent on the result of the first roll.
Compute the value of P (A) as follows:
Favorable outcomes = {1, 2} = 2
P (A) = Favorable outcomes of A ÷ Total number of outcomes
[tex]=\frac{2}{6}[/tex]
[tex]=\frac{1}{3}[/tex]
Compute the value of P (B) as follows:
Favorable outcomes = {2, 3, 5} = 3
P (B) = Favorable outcomes of B ÷ Total number of outcomes
[tex]=\frac{3}{6}[/tex]
[tex]=\frac{1}{2}[/tex]
Compute the probability of rolling a number less than or equal to 2, then rolling a prime number as follows:
[tex]P(A\cap B)=P(A)\times P(B)[/tex]
[tex]=\frac{1}{3}\times \frac{1}{2}[/tex]
[tex]=\frac{1}{6}[/tex]
Thus, the probability of rolling a number less than or equal to 2, then rolling a prime number is [tex]\frac{1}{6}[/tex].