Question

Rachel burns a 53 gram cracker under a soda can filled with 68.7 grams of water. She took the temperature of the water before she began -- it was 5.5 degrees Celsius. After the cracker was done burning, the temperature of the water was 73.1 degrees Celsius. How many calories of heat were released by the cracker? Round your answer to one digit after the decimal point.

Answer 1

Answer:

nobody on here has answer

Answer 2

The amount of calories of heat released by the cracker into the water is 4644.12 calories

Data obtained from the question

• Mass of cracker = 53 g
• Mass of water = 68.7 g
• Initial temperature of water = 5.5 °C
• Final temperature of water = 73.1 °C
• Heat released by cracker = ?

How to determine the heat released by cracker

Heat released by cracker = Heat gained by water

Thus, we shall determine the heat gained by the water in order to determine the heat released by the cracker. This can be obtained as follow:

• Mass of water (M) = 68.7 g
• Initial temperature (T₁) = 5.5 °C
• Final temperature (T₂) = 73.1 °C
• Change in temperature (ΔT) = 73.1 – 5.5 = 67.6 °C
• Specific heat capacity (C) = 1 Cal/g°C
• Heat (Q) =?

Q = MCΔT

Q = 68.7 × 1 × 67.6

Q = 4644.12 calories

Thus, the heat released by the cracker is 4644.12 calories

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