Answer:
Since we don't know the population deviation [tex]\sigma[/tex] we need to use a t statistic, and the degrees of freedom are given by:
[tex] df = n-1= 15-1 =14[/tex]
The significance level is [tex]\alpha=0.1[/tex] so we need to look in the t distribution with df =14 a value who accumulates [tex]\alpha/2=0.05[/tex] of the area on each tail and we got:
[tex] t_{cric}= \pm 1.761[/tex]
And the non rejection zone of the null hypothesis would be:
d. Between -1.761 and 1.761
Step-by-step explanation:
For this case the sample size is n =15. We want to conduct a two tailed test in order to check if the true mean is equal to a specified value
Null hypothesis: [tex]\mu =\mu_o [/tex]
Alternative hypothesis: [tex]\mu \neq \mu_o [/tex]
Since we don't know the population deviation [tex]\sigma[/tex] we need to use a t statistic, and the degrees of freedom are given by:
[tex] df = n-1= 15-1 =14[/tex]
The significance level is [tex]\alpha=0.1[/tex] so we need to look in the t distribution with df =14 a value who accumulates [tex]\alpha/2=0.05[/tex] of the area on each tail and we got:
[tex] t_{cric}= \pm 1.761[/tex]
And the non rejection zone of the null hypothesis would be:
d. Between -1.761 and 1.761