A paint company produces glow in the dark paint with an advertised glow time of 15 min. A painter is interested in finding out if the product behaves worse than advertised. She sets up her hypothesis statements as H0 : µ ≤ 15 and Ha : µ > 15, then calculates a test statistic of z = −2.30. What would be the conclusions of her hypothesis test at significance levels of α = 0.05, α = 0.01, and α = 0.001?

Respuesta :

Answer:

[tex] p_v = P(z<-2.30) =0.0107[/tex]

Now we can decide based on the significance level [tex]\alpha[/tex]. If [tex]p_v <\alpha[/tex] we reject the null hypothesis and in other case we FAIL to reject the null hypothesis.

[tex]\alpha=0.05[/tex] we see that [tex] p_v< \alpha[/tex] so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 15

[tex]\alpha=0.01[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

[tex]\alpha=0.001[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

Explanation:

For this case they conduct the following system of hypothesis for the ture mean of interest:

Null hypothesis: [tex]\mu \leq 15[/tex]

Alternative hypothesis: [tex]\mu >15[/tex]

The statistic for this hypothesis is:

[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And on this case the value is given [tex] z = -2.30[/tex]

For this case in order to take a decision based on the significance level we need to calculate the p value first.

Since we have a lower tailed test the p value would be:

[tex] p_v = P(z<-2.30) =0.0107[/tex]

Now we can decide based on the significance level [tex]\alpha[/tex]. If [tex]p_v <\alpha[/tex] we reject the null hypothesis and in other case we FAIL to reject the null hypothesis.

[tex]\alpha=0.05[/tex] we see that [tex] p_v< \alpha[/tex] so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 15

[tex]\alpha=0.01[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

[tex]\alpha=0.001[/tex] we see that [tex] p_v> \alpha[/tex] so then we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is NOT significantly less than 15

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