Answer:
4,712 fingerlings
Explanation:
The amount that a sum will accumulate to at the end of a particular number of period if it grows at a certain rate per annum is given as
F= A× (1+g)^(n)
F- Sum at the end of the period, A- sum at the beginning of the period, n- number of period, g -growth rate
5,000= A× (1.02)^(3)
a= 5000/(1.02^3)
a= 4711.61
The population at the start of fingerlings = 4,712
