You have a series of four chemical reactions (1 --> 2 --> 3 --> 4). How do you calculate the (triangle) H2 if you know the other (triangle)H values?

The value of ΔH₂ will be calcultaed as ΔH₂ = ΔH₄ - (ΔH₁ + ΔH₂).
Change in enthalpy of the reaction gives idea about the amount of heat released or absorbed during any chemical reaction.
In the question it is mention that series of four chemical reactions are from 1 to 4, means 4th one is the last reaction. So the calculation of the change in enthalpy is represented as:
ΔH₁ + ΔH₂ + ΔH₃ = ΔH₄
Value of ΔH₂, will be calculated as-
ΔH₂ = ΔH₄ - (ΔH₁ + ΔH₂)
Hence, option (1) is correct.
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