The ball's height( in meters above the ground), x seconds after Amir threw it, is modeled by : h(x)=-(x-2)^2 +16 what is the height of the ball at the time its thrown?

Respuesta :

Answer:

20 m

Step-by-step explanation:

The height of the ball in metres is given as:

[tex]h(x) = (x-2)^2 + 16[/tex]

where xis time, in seconds.

At the instant that the ball is thrown, the time is 0 seconds. This means that the height will be h(0):

[tex]h(0) = (0 - 2)^2 + 16\\\\\\h(0) = (-2)^2 + 16\\\\\\h(0) = 4 + 16\\\\\\h(0) = 20 m[/tex]

The height of the ball is 20 metres.

Answer:

12 m

Step-by-step explanation:

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