Answer:
20 m
Step-by-step explanation:
The height of the ball in metres is given as:
[tex]h(x) = (x-2)^2 + 16[/tex]
where xis time, in seconds.
At the instant that the ball is thrown, the time is 0 seconds. This means that the height will be h(0):
[tex]h(0) = (0 - 2)^2 + 16\\\\\\h(0) = (-2)^2 + 16\\\\\\h(0) = 4 + 16\\\\\\h(0) = 20 m[/tex]
The height of the ball is 20 metres.