Respuesta :
Answer:
1) Stunt car A experiences a large stopping force over a short period of time.
2 stunt car B experiences a small stopping force over a longer period of time
3) stunt car A will sustain more damage than stunt car B
Explanation:
the mass and speed of both stunt cars are equal.
Mass = 43.3kg
Speed = 70.7 m/s
Their initial momentum = mv = 43.3 x 70.7 = 3061.31 kg-m/s
Their final momentum will be equal to zero since they come to a complete stop.
The rate of change of momentum = 3061.31 - 0 = 3061.31 kg-m/s
Rate of change of momentum = impulse
Impulse = force times time duration of impact
I = f x t
From this equation, the answers it can be seen that a shorter time duration of impact will produce a large force and vice versa.
Answer:
uhhhhmmmmm
Explanation:
i thinknijvnijanhjcnqehcnehhpnvhvhv h n h nhwbjjjjjhrewjnnnnnnnnnnnnnnnnnnnnnnnnnehghng
the
et tt t
hb tfhb
exactly im so smart lol