Question

The number of people enrolled in Math 101 at a certain community college is given by 200 - 5y, where y is the number of years since 2004. initial value = rate of change =

Answer 1

Answer:

Initial value = 200

Rate of change = -5

Step-by-step explanation:

We are given the following in the question:

Let x be the number of people enrolled in Math 101 at a certain community college.

Then, we are given the equation:

$x = 200-5y$

where y is the number of years since 2004.

Initial value:

Initial value is the value when y = 0. It is the number of people enrolled in Math 101 at a certain community college in year 2004.

Putting  y = 0, we get,

$x = 200-5(0)\\x = 200$

Initial value = 200

Rate of change:

Comparing to general linear equation,

$x = my +c$

where m is the rate of change and c is the intercept.

m = -5

It tells us that with increase in 1 unit of y, x decreases by 5 units i.e. every year the number of people enrolled in Math decreases by 5.

Rate of change = -5