Balanced chemical equation for the reaction is:
2S[tex]O_{2}[/tex] (g) + [tex]O_{2}[/tex] (g)+ 2[tex]H_{2}[/tex]O (l) ⇒[tex]H_{2} S_{} O_{4}[/tex]
Moles of [tex]H_{2} S_{} O_{4}[/tex] formed is 5.75 moles.
Moles of oxygen used is 5.75 moles in the reaction.
Explanation:
Data given:
moles of S[tex]O_{2}[/tex] = 11.5 moles
moles of [tex]H_{2} S_{} O_{4}[/tex] = ?
Moles of [tex]O_{2}[/tex] needed =?
balanced equation with states of matter =?
Balanced chemical reaction under STP condition is given as:
2S[tex]O_{2}[/tex](g) + [tex]O_{2}[/tex] (g) + 2[tex]H_{2}[/tex]O (l) ⇒[tex]H_{2} S_{} O_{4}[/tex]
From the balanced reaction 2 moles of sulphur dioxide reacted to form 1 mole of sulphuric acid:
so, from 11.5 moles of S[tex]O_{2}[/tex], x moles of [tex]H_{2} S_{} O_{4}[/tex] is formed
[tex]\frac{1}{2} =\frac{x}{11.5}[/tex]
2x = 11.5
x = 5.75 moles of sulphuric acid formed.
From the balanced reaction 1 mole of oxygen reacted to form 1 mole of sulphuric acid.
when 11.5 moles of Sulphur dioxide reacted then oxygen in the reaction is 5.75 moles.