[tex]x-\dfrac{3}{5}=\dfrac{7}{10}\ \ \ \ |add\ \dfrac{3}{5}\ to\ both\ sides\\\\x=\dfrac{7}{10}+\dfrac{3}{5}\\\\x=\dfrac{7}{10}+\dfrac{3\cdot2}{5\cdot2}\\\\x=\dfrac{7}{10}+\dfrac{6}{10}\\\\x=\dfrac{7+6}{10}\\\\x=\dfrac{13}{10}\\\\\boxed{x=1\dfrac{3}{10}}[/tex]
