Answer:
4.5kg/min
Explanation:
Given parameters
[tex]T_1 = 32^0 C, m_1 = 3 kg/min, T_2 = 7^0 C ,T_3 = 17^0[/tex]
if we take
The mass flow rate of the second stream = [tex]m_2(kg/min)[/tex]
The mass flow rate of mixed exit stream = [tex]m_3 (kg/min)[/tex]
Now from mass conservation
[tex]m_3 = m_2 + m_1[/tex]
[tex]m_3 = m_2 + 3 (kg/min)[/tex]
The temperature of the mixed exit stream given as
[tex]T_3m_3 = T_2m_2 +T_1m_1\\\\17 ( 3 + m_2) = 7 \times m_2 + 32 \times 3\\\\51 + 17 m_2 = 7 m_2 + 96\\\\10 m_2 = 96 - 51\\\\m_2 = 4.5 kg/min\\\\\\\\[/tex]
Therefore the mass flow rate of second stream will be 4.5 kg/min.