Question

Graph a line that contains the point (-5,-3) and has a slope of -2

Answer 1

Answer:

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Step-by-step explanation:

Graph (-5,-3) and use the slope, -2, to find another point. -2 can also be written as $-\frac{2}{1}$

$\frac{rise}{run} =\frac{-2}{1}$ and  $\frac{rise}{run} =\frac{2}{-1}$ **

Use both. This works because either way, they will lie on the same line with the same slope. So, starting at (-5,-3), go down two points (-)* and to the left 1 (+)*, then, starting at (-5,-3) again, go up two points (+)* then to the right 1 point (-)*.

* If the number is negative, you either go down or to the right. If the number is positive, you go up and to the left.

**Rise over run refers to the change in the y-axis and the change in the x-axis: $\frac{rise}{run} =\frac{y-axis}{x-axis}$. Only one number is negative because, if both were negative, that would make a positive number, but the slope is -2, not 2.

Another way you could do this is by finding points first. All you need to do is turn the slope into a "point". Remember, 2 is the y and 1 is the x:

$-2=-\frac{2}{1} = (1,-2)$ and $(-1,2)$

Then, using (-5,-3) and your new points, add them separately:

$(-5,-3)+(1,-2)\\(-5+1,-3+(-2))\\(-5+1,-3-2)\\(-4,-5)$

(-4,-5) is one point

$(-5,-3)+(-1,2)\\(-5+(-1),-3+2)\\(-5-1,-3+2)\\(-6,-1)$

(-6,-1) is another point. Connect the three points. You can check your work on the graph:

Answer 2

The equation of the line is y = -2x - 7 and the graph is attached

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

The equation of the line that contains the point (-5,-3) and has a slope of -2 is:

$y-y_1=m(x-x_1)\\\\y-(-3)=-2(x-(-5))\\\\y+3=-2(x+5)\\\\y=-2x-13$

The equation of the line is y = -2x - 13 and the graph is attached

Find out more at: https://brainly.com/question/13911928