emilykain9895 emilykain9895

20-04-2020
Chemistry

contestada

what volume in ML of 12.0M HCL is needed to contain 3.00 moles of HCL?

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emaikwuvictor emaikwuvictor

23-04-2020

Answer:

V= 250ml

Explanation:

From n= CV

3= 12×V

V= 0.25L= 250ml

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