Answer:
Vector equation of the line ⇒ (x-1 , y-5) = t(-7,2)
Parametric equations ⇒ x = 1 - 7t and y = 5 + 2t
Step-by-step explanation:
Let the line L through (x,y) and through point P(1,5) and is parallel to a = (-7,2)
so, the vector equation of the line will be:
(x,y) - (1,5) = t(-7,2)
∴ (x-1 , y-5) = t(-7,2)
The parametric equations of the line will be:
x - 1 = -7t ⇒ x = 1 - 7t
y - 5 = 2t ⇒ y = 5 + 2t