Question

Simplify each expression.
$\frac{2x - 16}{8x ^{3} + 56x {}^{2} } \times \frac{x + 7}{x ^{2} - 7x - 8 }$
​

Answer 1

Answer:1

Step-by-step explanation: yea

Answer 2

Answer:

$\frac{1}{4x^2\left(x+1\right)}$

Step-by-step explanation:

$\frac{2x-16}{8x^3+56x^2}\cdot \frac{x+7}{x^2-7x-8}$

You first factor things out.

$\frac{x-8}{4x^2\left(x+7\right)}\cdot \frac{x+7}{x^2-7x-8}$

You then multiply. (Cancel common factor, X+7)

$\frac{x-8}{4x^2\left(x^2-7x-8\right)}$

You factor again.

$\frac{x-8}{4x^2\left(x+1\right)\left(x-8\right)}$

Then cancel out common fact x-8.

So therefore, you get the final answer,

$\frac{1}{4x^2\left(x+1\right)}$