Question

Calculate the total resistance in a series circuit made up of resistances of 3Ω, 4Ω, and 5Ω.

Answer 1

The total resistance in a series circuit is equal to the sum of all resistors (R total = ΣRi).

R total = R1 + R2 + R3 = (3 + 4 + 5) Ω = 12 Ω

Answer 2

The resistance means resist, means to resist the current, so we are here given that, three resistors are connected in series, so as we know that, if n resistors are connected in series combination, then the total resistance is the individual sum of all n Resistors, so if we apply the same formula here, we will be having :

${:\implies \quad \sf R_{Total}=3+4+5}$

${:\implies \quad \boxed{\bf{R_{Total}=12\Omega}}}$

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