Question

Consider this system of equations. Which shows the first equation written in slope-intercept form?

One-half (2 y + 10) = 7 x. y = 8.
y = 7 x minus 10
y = StartFraction 7 Over 2 EndFraction x minus 5
y = 7 x minus 5
y = StartFraction 7 Over 4 EndFraction x minus 5

Answer 1

the answer is c

.

.................

Answer 2

The equation in slope intercept form is y = 7x - 5

Given the equation 1/2(2y + 10) = 7x

We are to write it in slope-intercept form. The slope-intercept form is expressed as y = mx + b

Given

• 1/2(2y + 10) = 7x

Cross multiply:

• 2y + 10 = 2(7x)
• 2y + 10 = 14x

Subtract 10 from both sides

• 2y + 10 - 10 = 14x  - 10
• 2y = 14x -10

Divide both sides by 2

y = 14x/2 - 10/2

y = 7x - 5

Hence the equation in slope intercept form is y = 7x - 5

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