Step-by-step explanation:
The price of computer = 850
The price of computer after 2 years = 306
By compound depreciation,
[tex]Pn = P (1 - \frac{R}{100} ) ^ T[/tex] ... (i)
where Pn = 306
P = 850
R = rate of interest to be calculated
T = 2( number of years)
substituting the values in equation (1), we get
[tex]306 = 850 (1 - \frac{R}{100} ) ^ 2[/tex]
0.6 = 1 - [tex]\frac{R}{100}[/tex]
R = 40%
The worth after 5 years =
[tex]Pn = 850 (1 - \frac{40}{100} ) ^ 5[/tex]
Pn = 850 (0.077)
= $66.096 = $ 66
The computer be worth after 5 years = $ 66 (option B)