Question

If a spring has a spring constant of 1.00 × 10^3 N/m, what is the restoring force when the mass has been displaced 20.0 cm?

Answer 1

The spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.

Explanation:

When a spring is stretched or compressed its length changes by an amount x from its equilibrium length then the restoring force is exerted.

spring constant is k = 1.00 * 10^3 N/m

mass is x = 20.0 cm

According to Hooke's law, To find restoring force,

    F = - kx

        = - 1.00 *10 ^3 * 20.0

     F = 20000 N/m

Thus, the spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.

Answer 2

The mass that should be displaced 20.0 cm should be 20000 N/m.

Calculation of the mass:

At the time When a spring should be stretched or compressed its length so it changed by an amount x from its equilibrium length due to which the restoring force is exerted.

here,

spring constant is $k = 1.00 * 10^3 N/m$

mass is x = 20.0 cm

Now

As per Hooke's law

We know that

F = - kx

$= - 1.00 *10 ^3 * 20.0$

F = 20000 N/m

Hence, The mass that should be displaced 20.0 cm should be 20000 N/m.

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