Question

What is the equation, in slope-intercept form, of the line
that is perpendicular to the given line and passes through
the point (2, -1)?
y=- 2x - 2 / 2
y=- 2x - 5 / 5
y = 3x - 3
y = 3x - 7

Answer 1

Given:

Given that the graph of the equation of the line.

The line that is perpendicular to the given line and passes through the point (2,-1)

We need to determine the equation of the line perpendicular to the given line.

Slope of the given line:

The slope of the given line can be determined by substituting any two coordinates from the line in the slope formula,

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting the coordinates (-1,3) and (2,2), we get;

$m_1=\frac{2-3}{2+1}$

$m_1=-\frac{1}{3}$

Thus, the slope of the given line is $m_1=-\frac{1}{3}$

Slope of the perpendicular line:

The slope of the perpendicular line can be determined by

$m_2=-\frac{1}{m_1}$

Substituting $m_1=-\frac{1}{3}$, we get;

$m_2=-\frac{1}{-\frac{1}{3}}$

simplifying, we get;

$m_2=3$

Thus, the slope of the perpendicular line is 3.

Equation of the perpendicular line:

The equation of the perpendicular line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting $m=3$ and the point (2,-1) in the above formula, we have;

$y+1=3(x-2)$

$y+1=3x-6$

     $y=3x-7$

Thus, the equation of the perpendicular line is $y=3x-7$

Hence, Option d is the correct answer.