blguegba2n3ny
blguegba2n3ny
31-07-2016
Mathematics
contestada
F=9/5C+32, solve for C
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dalendrk
dalendrk
31-07-2016
[tex]\dfrac{9}{5}C+32=F\ \ \ \ |subtract\ 32\ from\ both\ sides\\\\\dfrac{9}{5}C=F-32\ \ \ \ |multiply\ both\ sides\ by\ \dfrac{5}{9}\\\\\boxed{C=\frac{5}{9}(F-32)}[/tex]
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Ckaranja
Ckaranja
07-08-2016
F=9/5C+32
F-32=9/5C
9/5C=F-32
9C=5(F-32)
C=[tex] \frac{5(F-32)}{9} [/tex]
Answer Link
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