The theoretical probability of the event a numbers is P(1),P(2),P(3),P(4),P(5),P(6) is.16,.18,.22,.1,.15,.19 respectively solved below.
Step-by-step explanation:
Given : A die is rolled 200 times with the following results.
Outcome 1 2 3 4 5 6
Frequency 32 36 44 20 30 38
Event - P(1),P(2),P(3),P(4),P(5),P(6),
To find : What is the theoretical probability of the given event?
Solution : .
Probability is defined as division of favorable outcome by total number of outcome.
Therefore, the theoretical probability of the event a numbers are as follow:
P(1)=[tex]\frac{32}{200}[/tex] =.16
P(2)=[tex]\frac{36}{200}[/tex]=.18
P(3)=[tex]\frac{44}{200}[/tex]=.22
P(4)=[tex]\frac{20}{200}[/tex]=.10
P(5)=[tex]\frac{30}{200}[/tex]=.15
P(6)= [tex]\frac{38}{200}[/tex]=.19
Therefore, the theoretical probability of the event a number for given is above.