Answer:
0.0676 moles of oxygen gas is produced
Explanation:
Step 1: Data given
Volume of the flask = 730 mL = 0.730 L
The pressure of the gas in the flask is 2.5 atm
The temperature is recorded to be 329 K
Step 2: The balanced equation
2NO3- → 2NO2- + O2
Step 3: Calculate moles oxygen gas (O2)
p*V =n * R*T
⇒with p = the pressure of oxygen gas = 2.5 atm
⇒with V = the volume of the flask = 0.730 L
⇒with n = the number of moles O2 gas
⇒with R = the gas constant = 0.0821 L*atm/mol*K
⇒with T ⇒ the temperature = 329 K
n = (p*V) / (R*T)
n = (2.5 * 0.730 ) / (0.0821*329)
n = 0.0676 moles
0.0676 moles of oxygen gas is produced