Question

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A company’s mean salary is $65,000 with a standard deviation of $6,000. What is the probability that an employee makes between $70,000 and $80,000?

Answer 1

Answer:

0.19706

Step-by-step explanation:

-Given the mean salary is $65,000 and the standard deviation is $6,000, the probability of making between $70000 and 80000 can be calculated as:

$P(70000<X<80000)=P(\frac{X_1-\mu}{\sigma}<z<\frac{X_2-\mu})\\\\=P(\frac{70000-65000}{6000}<z<\frac{80000-65000}{6000})\\\\=P(0.8333<z<2.5)\\\\\\=0.99379-0.79673\\\\=0.19706$

Hence,the probability that an employee makes between $70,000 and $80,000 is 0.19706