Question

Step A: a (x + StartFraction b Over 2 a EndFraction) squared = –c + StartFraction b squared Over 2 a EndFraction a (x + StartFraction b Over 2 a EndFraction) squared = StartFraction negative 4 a c + b squared Over 4 a EndFraction Step B: a (x + StartFraction b Over 2 a EndFraction) squared = StartFraction negative 4 a c + b squared Over 4 a EndFraction (one-half) a (x + StartFraction b Over 2 a EndFraction) squared = (StartFraction 1 Over a EndFraction)(StartFraction b squared minus 4 a c Over 4 a EndFraction) Determine the justification for the steps from the derivation of the quadratic formula. Justification of step A: Justification of step B:

Answer 1

Answer:

Justification of step A: common denominator

Justification of step B: multliplication property of equality

Step-by-step explanation:

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Answer 2

The justification for the steps from the derivation of the quadratic formula of step A is the use of common denominator.

The justification for the steps from the derivation of the quadratic formula of step A is the use of multiplication property of equality.

The given equations for step A;

$a(x + \frac{b}{2a} )^2 = -c + \frac{b^2}{2a} \\\\a (x + \frac{b}{2a} )^2= \frac{-4ac + b^2}{4a}$

The given equations for step B;

$a (x + \frac{b}{2a} )^2 = \frac{-4ac + b^2}{4a} \\\\\frac{1}{2} a(x + \frac{b}{2a} )^2 = (\frac{1}{a} )(\frac{b^2- 4ac}{4a} )$

The justification for the steps from the derivation of the quadratic formula of step A is determined as follows;

• The common denominator 4a was used to convert the mixed fraction into improper fraction.

The justification for the steps from the derivation of the quadratic formula of step B is determined as follows;

• The use of multiplication property of equality.

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