Question

A car travelling along a horizontal road accelerates from rest to a speed of 120km/h in T seconds, covering a distance of 88 8/9 metres in this time.

The car’s acceleration, a ms^-2, at times t seconds, is proportional to t.
Friend T and the value of a at this time.

Answer 1

Answer:

a = 6.25 m/s²

T = 5⅓ seconds

Step-by-step explanation:

a = (v - u)/t

v = 120×1000/3600 = 100/3

a = 100/3t

v² = u² + 2as

(100/3)² = 2(100/3t)(88 8/9)

10000/9 = (200/3t)(800/9)

200/3t = 12.5

t = 5⅓ seconds

a = 6.25