Answer:
64°
Step-by-step explanation:
In circle with center P, AD is diameter.
[tex] \therefore m\angle DPE + m\angle APE = 180\degree \\
\therefore (33k-9)\degree + 90\degree = 180\degree \\
\therefore (33k-9)\degree = 180\degree -90\degree \\
\therefore (33k-9)\degree = 90\degree \\
\therefore 33k-9 = 90\\
\therefore 33k= 90+9\\
\therefore 33k= 99\\
\therefore k= \frac{99}{33}\\
\therefore k=3\\
m\angle CPD = (20k +4)\degree \\
\therefore m\angle CPD = (20\times 3 +4)\degree \\
\therefore m\angle CPD =(60+4)\degree \\
\therefore m\angle CPD =64\degree \\
m\overset {\frown}{CD} = m\angle CPD\\
\therefore m\overset {\frown}{CD} = 64\degree
[/tex]
