Question

Please help me with these square root problems, Part 1. Please show and check the work.

$1. \sqrt{2x-5} - \sqrt{x+6} =0\\\\2. \sqrt{2x-5} + \sqrt{x+6}=0\\ \\3. \sqrt{x-5} - \sqrt{x+6}= 2\\ \\4. \sqrt{2x-5} -\sqrt{x+6}=2$

Answer 1

Answer:

x = 11

Step-by-step explanation:

sqrt (2x - 5) = sqrt (x + 6)

Square both sides

2x - 5 = x + 6

x = 11

Verify:

sqrt[2(11) - 5] = sqrt(11 + 6)

sqrt(17) = sqrt(17)

Answer 2

Answer:

x = 11

Step-by-step explanation:

√2x-5 - √x+6 = 0

√2x-5 = √x+6

(√2x-5)² = (√x+6)²

2x - 5 = x + 6

2x - x = 6 + 5

x = 11