Question

During a 12-hour period, the temperature in a city dropped from a high of 66°F to a low of −29°F. What was the range of the temperatures during this period?

Answer 1

Answer:

95

Step-by-step explanation:

66-66=0

0-29=-29

66+29=95

Answer 2

The range of the temperatures during this period is 95.

Given the following data:

• Time period = 12 hours

• Highest temperature = 66°F

• Lowest temperature = −29°F

To determine the range of the temperatures during this period:

Range is simply calculated by taking the difference between the highest number and the lowest number in a sample.

Mathematically, range is given by the formula;

$Range = highest \;number -lowest \;number$

Substituting the given parameters into the formula, we have;

$Range = 66-(-29)\\\\Range =66+29$

Range = 95

Therefore, the range of the temperatures during this period is 95.

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