Which point lies on the circle represented by the equation x2 + (y − 12)2 = 252?
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Answer:
A) (20,-3)
Step-by-step explanation:
we know that
If a ordered pair lie on the circle, then the ordered pair must satisfy the equation of the circle
we have
[tex]x^{2} +(y-12)^2=25^2[/tex]
The center of the circle is the point (0,12) and the radius is r=25 units
Verify
A) (20,-3)
substitute the value of x and y in the equation and then analyze the result
[tex]20^{2} +(-3-12)^2=25^2[/tex]
[tex]625=625[/tex] ----> is true
therefore
The ordered pair lie on the circle
B) (-7,24)
substitute the value of x and y in the equation and then analyze the result
[tex]-7^{2} +(24-12)^2=25^2[/tex]
[tex]193=625[/tex] ----> is not true
therefore
The ordered pair not lie on the circle
C) (0,13)
substitute the value of x and y in the equation and then analyze the result
[tex]0^{2} +(13-12)^2=25^2[/tex]
[tex]1=625[/tex] ----> is not true
therefore
The ordered pair not lie on the circle
D) (-25,-13)
substitute the value of x and y in the equation and then analyze the result
[tex]-25^{2} +(-13-12)^2=25^2[/tex]
[tex]1,250=625[/tex] ----> is not true
therefore
The ordered pair not lie on the circle