We have been given that the volume of a cone is 113.04 cubic mm. We are asked to find the approximate volume of a sphere that has the same height and a circular base with the same diameter.
We know that volume of cone is [tex]\frac{1}{3}\pi r^2\cdot h[/tex].
The height is equal to the diameter. We know that diameter is 2 times radius, so we can represent this information in an equation as:
[tex]h=2r[/tex]
Upon substituting [tex]h=2r[/tex] in volume of cone, we will get:
[tex]V=\frac{1}{3}\pi r^2\cdot 2r[/tex]
[tex]V=\frac{2}{3}\pi r^3[/tex]
We know that volume of sphere is [tex]V=\frac{4}{3}\pi r^3[/tex].
Upon comparing volume of cone with volume of sphere, we can see that volume of sphere is 2 times the volume of cone.
[tex]V=2(\frac{2}{3}\pi r^3)[/tex]
Since [tex]\frac{2}{3}\pi r^3=113.04[/tex], so volume of sphere would be:
[tex]V=2(113.04)[/tex]
[tex]V=226.08[/tex]
Therefore, volume of sphere would be 226.08 cubic mm.