Question

If 211 mL of water is added to 5.00 mL of 3.24 M NaCl solution,
what is the concentration of the dilute solution?

Answer 1

Answer:

0.075M

Explanation:

-The concentration of a solution is defined as the mass of the solute divided by the volume of the solution:

$Concentration=\frac{Mass \ Solute}{Volume \ of \ Solution}$

-We the solve the molarity problem as follows:

$M_1V_1=M_2V_2\\\\V_2=V_1+211=211+5=216mL\\\\\therefore M_2=\frac{M_1V_1}{V_2}\\\\=\frac{3.24\times 5}{216}\\\\\\=0.075\ M$

Hence, the concentration of the dilute solution is 0.075M